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This reaction could be classified as a double displacement reaction or a neutralization reaction (metal oxides have basic properties in water). So since the reactant =product, the equation is balance. How do I tun that into mL? Ask Question + … Since copper is a positive SRP metal it won't readily replace hydrogen in sulfuric acid and so the reaction does not proceed in this case. 0.01006 moles of CuO needs 0.01006 moles of H2SO4. your answer(2sigfigs): 1.7 millilitres. This reaction seems to favor the formation of copper(II) hydroxide, CuOH. However in copper (II) sulfate preparation you don't normally make the anhydrous salt CuSO4 but the blue hydrated salt CuSO4.5H2O. Still have questions? Cu + H2SO4 = CuSO4 + SO2 + H2O - Chemical Equation Balancer. 0 0. Anonymous. Product side(1mol of Cu,5moles of O,2moles of H and 1mol of S). Cuo H2so4. Copper (II) oxide will react with sulfuric acid to create water and copper (II) sulfate. The reaction completely depends on the concentration of sulphuric acid. Reactant side(1mol Cu,5moles of O,2moles of H and 1mol of S). Source(s): https://shorte.im/a9Kfh. Reactants. 1 decade ago. Cu + 2 H 2 SO 4 → CuSO 4 + SO 2 + 2 H 2 O. CuO+H2SO4---> CuSO4+H2O. find volume, using molarity's ratio: 0.01006 moles of H2SO4 @ 6.0 mol/litre = 0.001676 litres . So it would almost certain require you to work on I have already figured out that the molar mass of CuO is 80g and H2SO4 is 98 g. If I use 0.80g of CuO, then I will need 0.98g of H2SO4. 0 0. The acid dissociates one H+ ion, that is likely to be absorbed by the CuO molecule, and then turned into the insoluble CuOH molecule. CuO+H2SO4->CuSO4+H2O. Copper - Cu. Now I'm stuck. Copper + Sulfuric Acid = Cupric Sulfate + Sulfur Dioxide + Water . Balanced Chemical Equation. Reaction Information. Get your answers by asking now. How many milliliters of 6.0 M H2SO4 are required to react with 0.80 g of CuO according to Equation above? 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